A heavy nucleus at rest breaks into two fragments which fly off with velocity in the ratio 27:1
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Answer:
The answer is 1/3
Explanation:
According the problem the ratio of the velocity is 27:1
From the momentum conservation theory
m1v1= m2v
=>v1/v2= 27/`1 = m2/m1
=> m1/m2= 1/27
Now we know that mass can be written as m = v/d [ where v is the volume and d is the density]
But the particle breaks into fragments
therefore,
v a m
v1/v2= m1/m2
a1^3/a2^3= 1/27
a1/a2= 1/3
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