A heavy uniform chain lies on horizontal table top. If the
coefficient of friction between the chain and the table surface
is 0.25, then the maximum fraction of the length of the chain
that can hang over one edge of the table is
(a) 20% (b) 25%
(c) 35% (d) 15%
Answers
Explanation:
A heavy uniform chain lies on horizontal table top. If the
coefficient of friction between the chain and the table surface
is 0.25, then the maximum fraction of the length of the chain
that can hang over one edge of the table is
(a) 20% (b) 25%
(c) 35% (djsjkskskzidisididdiddkdkdkdxkdkdkdkdkiffkfkff) 15%
Answer:
20% HOPE YOU ENJOY THIS QUESTION...
Explanation:
Let x be the length of rope on table and (L−x) is the length hanging. Let total mass be M.
Therefore mass of hanged part & on table part are
L
M
(L−x)&
L
M
x respectively
Maximum Friction force: f
max
=μN=μ(
L
M
x)g=
L
μMgx
Weight of hanging chain: W=m
′
g=
L
M
(L−x)g=
L
M(L−x)g
For system to be stable:
L
M(L−x)g
=
L
μMgx
(L−x)=
4
1
x
x=
5
4
L
Therefore hanging part is
5
L
.(20%)