A helicopter is ascending vertically with a speed of 8 m/s. At a height of 120m above the Earth, a packet is dropped from a window. How much time does it take for the packet to reach the ground is n seconds, then value of n is
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Given: A helicopter is ascending vertically with a speed of 8 m/s and the correct height is 12 m instead of 120 m.
To find: How much time does it take for the packet to reach the ground?
Solution:
- We have given that A helicopter is ascending vertically with a speed of 8 m/s, so the initial velocity is 8 m/s.
- At a height of 12 m above the earth a packet is dropped from a window, so the height is 12 m.
- Let the time taken be n (as given in the question)
- Lets consider a = -g = -10 m/s² (as coming down so negative)
- Now we have the formula:
s = un + 1/2 x (-a)n²
-12 = 8n - 1/2 x 10n²
-12 = 8n - 5n²
5t² - 8n - 12 = 0
n = 2.53 seconds
Answer:
So the time taken n is 2.53 seconds.
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