Question

a helicopter lifts a 72kg astronaut 15 m vertically from the ocean by means of a cable. the acceleration of astronaut is g / 10. how much work is done on the astronaut by (g = 9.8 m / s2). the force from the helicopter

Answer 1

Mass of astronaut (m) = 72 kg

Acceleration of astronaut (a) = $\frac{g}{10}$

Force applied by the helicopter = m (a + g)

Force applied = $m \times ( g + \frac{g}{10} )$

Force applied = $\( m \times \frac{11g}{10} \)$

Work done by the force from the helicopter = Force applied × Displacement

Displacement = 15 m

Work done = $\frac{72 \times 11 \times 9.8 \times 15}{10}$

Work done = 11642.4 Joules

Hence, the work done by helicopter = 11642.4 Joules

Answer 2

Answer:

1] 11642.4 J

2] -10584.6 J

3] 1058J

4] 5.4 m/s