Question

a helicoptor rising vertically with a velocity of 20m/s release a food package at a height 1 above from the ground.ifthe object strikes the ground after 8 sec.
a,find the height
b,what'll be the velocity of the object when it strikes the ground
c,compute the position & velocity of the object 4 sec after it is released from the helicopter
d,how high will it rise above

Answer 1

Answer:

Look in the explanation.

Explanation:

Initial velocity of package = 20 m/s

Acceleration = 10 m/s^2

Time = 8 s

a) Height = 20×8 + 1/2 × 10 × 8 × 8 m = 160 + 320 m = 480 m

b) Final Velocity = 20 + 10 × 8 m/s = 20 + 80 m/s = 100 m/s

c)Time = 4s

Velocity = 20 + 10 × 4 = 60 m/s

Height = 20 × 4 + 1/2 × 10 × 4 × 4 = 160m

Position = 320 m above ground

d)It won't rise above.