Question

A Helium nucleus (charge +2e) completes one round of a circle 0.8 m in 2s. Find the magnetic field at the centre of the circle.

Answer 1

Answer:

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Answer 2

Answer:

ANSWER

The expression of magnetic field for an electron in a circular path is

B =

4πr

μ

o

2πNI

where, I= current, N= no. of rotation (Here in this case)= 1

B =

4πr

μ

o

2πI

=

2r

μ

o

I

We know that, Helium has 2 charges. And the formula of current I=

t

2e

Also magnetic field B =

2rt

μ

0

2e

=

rt

μ

0

2e

=(

0.8×2

1.67×10

−19

)×4π×10

−7

=12.56×10

−26

T