A Helium nucleus (charge +2e) completes one round of a circle 0.8 m in 2s. Find the magnetic field at the centre of the circle.
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The expression of magnetic field for an electron in a circular path is
B =
4πr
μ
o
2πNI
where, I= current, N= no. of rotation (Here in this case)= 1
B =
4πr
μ
o
2πI
=
2r
μ
o
I
We know that, Helium has 2 charges. And the formula of current I=
t
2e
Also magnetic field B =
2rt
μ
0
2e
=
rt
μ
0
2e
=(
0.8×2
1.67×10
−19
)×4π×10
−7
=12.56×10
−26
T
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