Question

A hemi spherical hollow bowl has material of volume 43π\3 cubic cm. It's external diameter is 14cm. Find its thickness

Answer 1

Answer:

I think in question there is 436π/3

Step-by-step explanation:

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Answer 2

Answer:

Let R, r be the external and internal radii of the hemispherical hollow.

GIVEN : External diameter = 14cm bowl,

External radius R = 7cm

Volume of the

hollow hemispherical bowl = 436π/3 Cu.cm

2/3 π(R^3 - r^3) = 436π/3

2/3 π(7^3 - r^3) = 436π/3

343 - r^3 = 436π/3 × 3/2π

343 - r^3 = 218

r^3 = 343 - 218 = 125

r^3 - 5^3 =>>>>> r = 5cm

• Internal radius r = 5cm
• Thickness = R - r = 7 - 5 = 2cm

∴ Thickness = 2cm.

Step-by-step explanation:

@SSR