Math, asked by niki801, 1 year ago

A hemisperical bowl is 0.25 com thick and it's inner radius is 5 cm find outer curved surface area and volume of bowl.

Answers

Answered by krantiprakashraushan
1
R of inner part =5cm
Then,r of outer part=5+0.25=5.25
V=2/3pie*r
=2/3*22/7*5.25*5.25*5.25
=303.1875cm^3
Curved surface area =2pie *r^2
=2*22/7*5.25*5.25
=173.25cm^2
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