A hemisphere boud is made of 0.2cm thick steel. The inner diameter of the bowl is 8cm. also find outer curved surface area of the bowl . also find the cost of polishing its outer surface at the rate of rupees 2 per cm
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Inner radius = 8/2 = 4 cm
outer radius = 4 + 0.2 cm = 4.2 cm
Outer curved surface area = 2 π 4.2² = 110.88 cm²
cost = 2*110.88 = Rs 221.76
outer radius = 4 + 0.2 cm = 4.2 cm
Outer curved surface area = 2 π 4.2² = 110.88 cm²
cost = 2*110.88 = Rs 221.76
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