a hemisphere bowl has a radius of 9cm. what would be the volume of water it would contain?
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Answer:
Radius of hemispherical bowl = 9 cm
Volume of liquid in the bowl =
3
2
πr
3
=(
3
2
π×9×9×9)=486π cm
3
Radius of each cylindrical bottle =
2
3
cm
And, height = 4 cm
Volume of each cylindrical bottle = πR
2
h=π×
2
3
×
2
3
×4=9π cm
3
Therefore, required number of bottles =
9π
486π
=54
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