Question

A hemisphere bowl is made up of brass 0.25 thickness.The inner radius of the ball is 5 cm . Find the ratio of outer surface area to inner surface area...?​

Answer 1

Step-by-step explanation:

Given the radius of hemisphere bowl is

5

cm and made by brass

0.25

cm thickness

Then outer radius of hemisphere bowl

=

5

+

0.25

=

5.25

cm

Then surface area of inner surface of hemisphere

=

4

π

r

2

=

4

×

π

×

(

5

)

2

=

100

π

Then surface area of outer surface of hemisphere

=

4

π

r

2

=

4

×

π

×

(

5.25

)

2

=

110.25

π

Then ratio of outer and inner surface area

=

110.25

π

100

π

=

110.25

100

Answer 2

It is given that the hemispherical bowl is made of brass of 0.25 cm thickness and the inner radius of the bowl is 5 cm. Therefore the ratio of outer surface area to inner surface area is 441 : 400.

.

.

.

I hope it help you....