Question

a hemisphere dome dome of a tomb needs to be painted. The circumference of the base of the domb is 17.6cm . if the cost of painting is 7rupees pe sq cm,what is the cost ,rounded to the nearest rupee,to paint the domb​

Answer 1

Since only the rounded surface of the dome is to be painted we need to find the curved surface area of the hemisphere to know the extent of painting that needs to be done. 

Now, circumference of base of the dome = 17.6 m   Therefore 17.6 = 2πr

So, The radius of the dome =17.6×7* 2*22m

= 2.8 m

The curved surface area of the dome =2πr^2

=2×22/7×2.8×2.8m^2

=49.28m^2

Now, cost of painting 100 cm^2 is Rs. 5

So, cost of painting 1 m^2 = Rs. 500

Therefore, cost of painting the whole dome

=Rs.500×49.28

=Rs.24640  

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