Question

A hemisphere of lead of radius 8cm is cast into a right circular cone of base radius 6 cm . Determine the height of the cone

Answer 1

Answer:

Step-by-step explanation:

28.4 m

Answer 2

AnswEr:

Let h be the height of the cone.

We have,

• Radius of hemisphere = 8 cm
• Radius of base of the cone = 6 cm

Now,

$\qquad$ Volume of the cone = Volume of the hemisphere

$\\ \colon \implies \sf \: \frac{1}{3} \times \pi \times {6}^{2} \times h = \frac{2}{3} \times \pi \times {(8)}^{3} \\ \\ \\ \colon \implies \sf \: 36h \: = 2 \times 512 \\ \\ \\ \colon \implies \sf \: h = \frac{1024}{36} \\ \\ \\ \colon \implies \sf \frac{256}{9} \\ \\ \\ \colon \implies \sf \blue {28.44 \: cm}$