a hemispherecal bowl of internal radius 15cm contains a liquid the liquid is to be filled into cylindrical shaped bottles of diameter 5cm and height 6cn how many bottles are necessary to empty the bowl
Answers
Answered by
0
volume of hemispherical bowl is 2*3.14*15*15
volume of cylindrical bottle 3.14*2.5*2.5*6
no. of bottle needed= volume of hemispherical bowl÷volume of cylindrical bottle
volume of cylindrical bottle 3.14*2.5*2.5*6
no. of bottle needed= volume of hemispherical bowl÷volume of cylindrical bottle
Answered by
1
radius of hemispherical ball = 15cm
volume of ball = 2/ 3* ( πr^3)
= 2/ 3 * ( 22 × (15)^3)/ 7
= 148500/ 21 cm^2
diameter of cylindrical bottle= 5cm
radius = 5 ÷ 2 = 2.5cm
height = 6cm
volume of cylindrical bottle
= πr^2h = 22 × (2.5)^2 ×6/ 7
= 825/ 7
number of bottles required to empty the ball
= (148500/ 21 ) ÷ (825/ 7)
= 148500× 7/ 21 × 825 = 60 bottles
Answer:
________
60 bottles are required to empty the ball.
volume of ball = 2/ 3* ( πr^3)
= 2/ 3 * ( 22 × (15)^3)/ 7
= 148500/ 21 cm^2
diameter of cylindrical bottle= 5cm
radius = 5 ÷ 2 = 2.5cm
height = 6cm
volume of cylindrical bottle
= πr^2h = 22 × (2.5)^2 ×6/ 7
= 825/ 7
number of bottles required to empty the ball
= (148500/ 21 ) ÷ (825/ 7)
= 148500× 7/ 21 × 825 = 60 bottles
Answer:
________
60 bottles are required to empty the ball.
Similar questions