A hemispherical bowl has diameter 9cm. The liquid is poured into cylindrical bottle of diameter 3cm. and height3cm If a bowl of liquid is filled in the bottles, find how many bottles are required .
Answers
Answered by
21
No. of bottles=volume of hemisphere/ volume of bottle
= 2/3πr³/πr²h
=2/3×22/7×(9/2)³/22/7×(3/2)²×3
=190.9/21.21
=9
= 2/3πr³/πr²h
=2/3×22/7×(9/2)³/22/7×(3/2)²×3
=190.9/21.21
=9
Answered by
15
Answer:
Step-by-step explanation:
GIVEN : For hemisphere:
Diameter = 9cm
Radius (R)= 9/2 = 4.5 cm
For cylinder :
Diameter = 3 cm
Radius (r)=3/2 = 1.5 cm
Height (h)=3cm
Let the no. of Cylindrical bottles = x
ATQ
Volume of hemisphere = Volume of cylinder × x
No. of Cylindrical bottles =Volume of hemisphere/Volume of cylinder
No. of Cylindrical bottles = 2/3πR³ / πr²h
No. of Cylindrical bottles = 2/3π(4.5)³ /π(1.5)² × 3
No. of Cylindrical bottles = 2/3× (4.5)³ / (1.5)² X 3
x = 2× 1.5 × 4.5 × 4.5 / 1.5 × 1.5 × 3
x = 2 × 4.5 = 9
x= 9
Hence, the no. of Cylindrical bottles required = 9.
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