Question

A hemispherical bowl has hasa radius of 3.5cm.What would ne the volume of water it would contain..
Answer fast...plzzz

Answer 1

The volume of water the bowl can contain,
$= \frac{2}{3}\pi {r}^{3}$
$= \frac{2}{3} \times \frac{22}{7} \times 3.5 \times 3.5 \times 3.5 {cm}^{3}$
$= 89.8 {cm}^{3}$

Answer 2

Idk............ .....