Question

A hemispherical bowl has radius of 3.5cm .what would be the volume of water it would contain ??

Answer 1

Heya frnd,
Volume =2/3πr^3
2/3*22/7*3.5*3.5*3.5
=89.83 something

Answer 2

Answer:

Volume of Hemispherical bowl is

$\frac{ 2}{3} \pi \: r {}^{2}$

2/3 × 22/7× (3.5)³ cm³

=> 89.3 cm³