A hemispherical bowl is made of brass, 0.25cm. thickness. The inner radius of the bowl is 5 cm. Find the ratio of outer surface area to inner surface area.
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Inner radius=5cm
surface area =4(pi)r²=100pi
Outer radius=5.25cm
surface area=4(pi)r²=110.25pi
ratio=1.1025
surface area =4(pi)r²=100pi
Outer radius=5.25cm
surface area=4(pi)r²=110.25pi
ratio=1.1025
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