Question

A hemispherical bowl is made of steel 0.25 centimetre thick the inner radius of the ball is 5 centimetre find the outer called surface area of the bowl

Answer 1

surface area of hemisphere=2πr^2
r=5.25
2*22/7*5.25*5.25=173.25

Answer 2

${\huge{\green{\underline{\underline{\pink{⇝Aηѕωєя \: :}}}}}}$

$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

${\huge{\red{\underline{\overline{\mathscr{\red{Hope \: This \: Helps \: You}}}}}}}$