Question

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bond
5 cm. Find the outer curved surface area of the bowl.​

Answer 1

Step-by-step explanation:

Total radius = 5+ 0.25 = 5.25 cm

CSA if hemisphere = 2×22/7×r²

= 2×22/7×5.25×5.25

= 173.25 cm²

Answer 2

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$\small\bold{Inner \: radius \: of \: the \: bowl \: = }$ 5cm

$\small\bold{Thickness \: of \: the \: steel \: =}$ 0.25cm

$\small\bold{Outer \: radius \: of \: the \: bowl \: =}$ 5+0.25=5.25cm

$\small\bold{Outer \: Curved \: surface \: of \: the \: hemispherical \: bowl \: =}$ 2πr²

= 2× $\large\dfrac{22}{7}$ × (5.25)² = 172.25 cm²

${\huge{\red{\underline{\overline{\mathscr{\red{Hope \: This \: Helps \: You}}}}}}}$