Question

A light ray, going through a prism with the angle of prism 60°, is found to deviate by 30°. What limit on the refractive index can be put from these data

Answer 1

Given :

Angle of prism =60

Angle of deviation= 30

μ= sin(A+Dm)/2 / Sin A/2

μ= Sin (60 +Dm)/2/ Sin 30

We know that one ray has been found out which is deviated by 30°, the angle of minimum deviation should be either equal or less than 30°.

μ≤2sin 60+dm/2

μ≤2x1/√2

μ≤√2

Answer 2

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ᴀɴɢʟᴇ ᴏғ ᴘʀɪsᴍ =60

ᴀɴɢʟᴇ ᴏғ ᴅᴇᴠɪᴀᴛɪᴏɴ= 30

μ= sɪɴ(ᴀ+ᴅᴍ)/2 / sɪɴ ᴀ/2

μ= sɪɴ (60 +ᴅᴍ)/2/ sɪɴ 30

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ᴏɴᴇ ʀᴀʏ ʜᴀs ʙᴇᴇɴ ғᴏᴜɴᴅ ᴏᴜᴛ ᴡʜɪᴄʜ ɪs ᴅᴇᴠɪᴀᴛᴇᴅ ʙʏ 30°, ᴛʜᴇ ᴀɴɢʟᴇ ᴏғ ᴍɪɴɪᴍᴜᴍ ᴅᴇᴠɪᴀᴛɪᴏɴ sʜᴏᴜʟᴅ ʙᴇ ᴇɪᴛʜᴇʀ ᴇǫᴜᴀʟ ᴏʀ ʟᴇss ᴛʜᴀɴ 30°.

μ≤2sɪɴ 60+ᴅᴍ/2

μ≤2x1/√2

μ≤√2