A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is
5 cm. Find the outer curved surface area of the bowl.
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Inner radius= 5cm
Hence outer radius = r = 5 + 0.25cm = 5.25cm
therefore,
outer curved surface = 2πr2
= 2 × 22/7 × 5.25 × 5.25
= 173.25cm2
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