a hemispherical bowl is made of steel 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.
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Answered by
225
Answer:
Step-by-step explanation:
Outer radius = inner radius + thickness 0.25cm + 5cm = 5.25cm c.s.a = 2pie rsquare 2× 22/7 × 5.25 × 5.25= 346.5 cm square
Answered by
238
Given
Inner radius = 5 cm
Hence outer radius = 5 +0.25=5.25
Therefore , outer curved surface area =2πr^2=2×22÷7×5.25×5.25
=173.25 cm^2
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