Question

A HEMISPHERICAL BOWL IS MADE OF STEEL 0.25 CM THICK. THE INNER RADIUS OF THE BOWL IS 5CM. FIND THE OUTER CURVED SURFACE AREA OF THE BOWL (PIE=22/7) PLS ANSWER I HAV MY EXAM COMING UP

Answer 1

Class 9 NCERT ch-13
Total diameter= 10 +0.25+0.25
=10.5
Radius= 5.25
C.s.a
2πr²=173.25cm²

Answer 2

Answer:

$173.25 cm^2$

Step-by-step explanation:

Inner radius of bowl = 5 cm

Thickness = 0.25 cm

Outer radius of bowl = 5+0.25 cm = 5.25 cm

Curved surface area of hemisphere = $2 \pi r^2$

Curved surface area of hemisphere = $2\times \frac{22}{7} \times (5.25)^2$

                                                          = $173.25 cm^2$

Hence the outer surface area of the bowl is $173.25 cm^2$