A hemispherical bowl is made of steel 0.25cm thick.The inner radius of bowl is 5cm. Find the outer C.S.A of the bowl(use π = 22/7)
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INNER RADIUS = 5cm
Hence, outer radius = r = 5+0.25cm = 5.25cm
Therefore, outer curved surface area = 2πr²
= 2*22/7*5.25*5.25
= 173.25cm
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