Question

A hemispherical bowl is made up of wood 0.5 CM thick. If inner radius of the bowl is 4 cm then find the volume of wood used to make the bowl??
Answer me wrong and get reported.

Answer 1

Inner radius(r) = 4 cm

Thickness of the wood= 0.5cm

∴Outer radius(R) = Inner radius (r) + Thickness of the wood

=4 + 0.5 = 4.5 cm

∴ Volume of the wood used to make the bowl = $\frac{2}{3}$πr³(R³-r³)

= $\frac{2}{3}$ x $\frac{22}{7}$ x { (4.5)³ - 4³ }

=2/3 x 22/7 (91.125 -64 )

=2/3 x 22/7 (27.125 )

=2/3 x 85.25

=56.83 cm³

If this helped you, please mark me as brainliest