Question

A hemispherical bowl made of brass has inner diameter 0.105 m. Find the cost of tin-plating it on the inside at the rate of rs 16 per 100 cm square

Answer 1

to find the inner cost of plating it, we must find the CSA of the bowl=2πr2
 radius=0.105m=0.105*100 cm
=10.5 diameter

radius=10.5/2= 5.25
 
now CSA=2*22/7* 5.25 * 5.25

=173.25 cm square

cost of tin plating=rs.16 /100cm square
cost for 173.25 cm square =173.25 * (1/ 100) * 16
=27.72
thus the cost of tin plating it inside = 27.72
 
hope it helps!!!!

Answer 2

Hi friend,
The diameter of the bowl = 0.105 m
The radius of the bowl= 0.105/2= 105/2000m
CSA of hemispherical bowl = 2πrsq.
CSA= 2×22/7×105/2000×105/2000 m sq.
CSA= 105×15×11/1000×1000
CSA= 0.017325 m sq.
= 173.25 cm sq.
Cost of tin plating = 173.25/100×16
Cost of tin plating = Rs. 27.72
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