A hemispherical bowl of internal diameter 36cm contains liquid. This liquid is filled into 72 cylindrical bottles of diameter 6 cm Find the height of the each bottle. If 10% liquid is wasted in this transfer .
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Heya !!!
Diameter of hemispherical bowl = 36 cm
Radius of hemispherical bowl = D/2 = 36/2 = 18
Volume = 2/3 πR³
=> 2/3 × 22/7 × 18 × 18 × 18
=> ( 2 × 22 × 6 × 18 × 18 ) / ( 7)
=> 85536/7
=> 12219.42 cm³
★ 10% of 12219.42
=> 10/100 × 12219.42
=> 1221.94 cm³
Diameter of cylindrical bottles = 6 cm
Radius of cylindrical bottle = D/2 = 3 cm
Volume of each cylindrical bottle = πR²H
=> (22/7 × 3 × 3 × H ) cm³
72(Volume of each cylindrical bottle ) = 1221.94
72 × ( 198×H/7 ) = 1221.94
72 × 28.28H = 1221.94
2036.16H = 1221.94
H = 1221.94/2036.16
H = 0.60 cm
★ HOPE IT WILL HELP YOU ★
Diameter of hemispherical bowl = 36 cm
Radius of hemispherical bowl = D/2 = 36/2 = 18
Volume = 2/3 πR³
=> 2/3 × 22/7 × 18 × 18 × 18
=> ( 2 × 22 × 6 × 18 × 18 ) / ( 7)
=> 85536/7
=> 12219.42 cm³
★ 10% of 12219.42
=> 10/100 × 12219.42
=> 1221.94 cm³
Diameter of cylindrical bottles = 6 cm
Radius of cylindrical bottle = D/2 = 3 cm
Volume of each cylindrical bottle = πR²H
=> (22/7 × 3 × 3 × H ) cm³
72(Volume of each cylindrical bottle ) = 1221.94
72 × ( 198×H/7 ) = 1221.94
72 × 28.28H = 1221.94
2036.16H = 1221.94
H = 1221.94/2036.16
H = 0.60 cm
★ HOPE IT WILL HELP YOU ★
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