Question

A hemispherical bowl of internal radius ,9 cm is full of liquid is to be filled into a cylindrical shaped bottles each of radius 1.5 cm and height is 4 cm how many bittles are needed to empty the bowl

Answer 1

Hey friend..!! here's your answer
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Radius of hemisphere bowl = 9cm

Radius of cylindrical shape bottle = 1.5 cm
height = 4cm

n = number of bottles needed to empty the bowl.
v
Volume of hemisphere = n× Volume of cylindrical bottles

$\frac{2\pi {r}^{3} }{3} = n \times \pi {r}^{2} h$

$\frac{2 \times 22 \times 9 \times 9 \times 9}{3 \times 7} =n \times \frac{22 \times 1.5 \times 1.5 \times 4}{7}$

$n = \frac{2 \times 22 \times 9 \times 9 \times 9 \times 7}{3 \times 7 \times 1.5 \times 1.5 \times 22 \times 4}$

$n = \frac{224532}{4158} \\ \\ n = 54$

So that 54 bottles needed to empty the hemispherical bowl.

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#Hope its help

Answer 2

Step-by-step explanation:

Radius of cylindrical shape bottle = 1.5 cm

height = 4cm

n = number of bottles needed to empty the bowl.

v

Volume of hemisphere = n× Volume of cylindrical bottles

\frac{2\pi {r}^{3} }{3} = n \times \pi {r}^{2} h

3

2πr

3

=n×πr

2

h

\frac{2 \times 22 \times 9 \times 9 \times 9}{3 \times 7} =n \times \frac{22 \times 1.5 \times 1.5 \times 4}{7}

3×7

2×22×9×9×9

=n×

7

22×1.5×1.5×4

n = \frac{2 \times 22 \times 9 \times 9 \times 9 \times 7}{3 \times 7 \times 1.5 \times 1.5 \times 22 \times 4}n=

3×7×1.5×1.5×22×4

2×22×9×9×9×7

\begin{gathered}n = \frac{224532}{4158} \\ \\ n = 54\end{gathered}

n=

4158

224532

n=54

So that 54 bottles needed to empty the hemispherical bowl.