Question

A hemispherical tank full of water is emptied by a pipe at the rate 3 $\dfrac{4}{7}$ litres per second . How much time will it take to empty half the tank , if it is 3m in diameter take π = 22/7

Answer 1

Answer:

$\dfrac{99000}{28}$×$\dfrac{7}{25}$

so ,, 16.5 minutes .

Step-by-step explanation:

=> Radius of hemispherical tank = $\dfrac{3}{2}$ m

=> volume of the tank = $\dfrac{2}{3}$×$\dfrac{22}{7}$ × $\dfrac{3}{2}$ ^3

=> $\dfrac{99}{14}$ m^3 .

=> therefore , the volume of the water to be emptied = $\dfrac{1}{2}$ ×$\dfrac{99}{14}$ m^3

=> $\dfrac{99}{28}×1000$

=> $\dfrac{99000}{28}$

=>since , $\dfrac{25}{7}$ litres of water is emptied in 1sec then $\dfrac{99000}{28}$ litres of water will be emptied in 16.5 mins .

=> As i showed $\dfrac{99000}{28}$×$\dfrac{7} {25}$

Final Answer :- 16.5 mins ✓