Question

A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius of the tamk is 1 m, then find the volume of the iron used to make the tank. (Use pie = 3.14)

Answer 1

iron sheet is 1cm = 0.01 m thick
inner radius is 1m
 so the radius of the tank becomes 0.01 + 1 = 1.01cm
Inner radius (r 1 )  = 1 m 
Thickness  = 1 cm = 0.01m 
Outer radius (r 2 )  = (1+ 0.01) m = 1.01 cm
Volume of hemisphere = 2/3 π( r 2  cube - r 2 cube ) 
V = 2/3 x 3.14 x ( 1.01 cube - 1 cube) cube
 V = 2/3 x 3.14 (1.030301 – 1)
 V = 2/3 x 3.14 x 0.030301
 V = 0.06343 m 3 

Answer 2

⇒ Answer :- 0.063487 cm^3

⇒ Given :-

Inner radius = 1 m

Iron sheet is 1 cm Thick

⇒ Solution :-

Let outer radius be R = Inner radius + thickness of iron sheet

= 101 cm

Inner radius be r = 1m = 100 cm

∴ Volume of the iron = (⅔)×(3.14)× (R^3-r^3)

(2/3)×(3.14)×(101^3-100^3)

44/21×30301 cm^3

63487.80952 cm^3

0.063487 cm^3