Question

A hemispherical tank made up of iron sheet 1 cm thick. If inner radius is 1 m, then find the volume of iron used to make the tank

Answer 1

Hi Friend ,


OA = r , inner radius ....

OB = R = Outer radius .....

r = 1 m = 100 cm

R = r + thickness = 100 cm + 1 cm = 101 cm

Volume of iron used = Total volume with R - Volume with radius 'r'
$= \frac{2}{3} \pi { R}^{3} - \frac{2}{3} \pi {r}^{3} \\ \\ = \frac{2}{3} \pi \times ( {R}^{ 3} - {r}^{3} ) \\ \\ = \frac{2}{3} \pi \times (1030301 - 1000000) \\ \\ = \frac{2}{3} \times \frac{22}{7} \times 30301 = 63487.8 {cm}^{3} = 63.4878 {m}^{3}$


Hope it helps

Answer 2

⇒ Answer :- 0.063487 cm^3

⇒ Given :-

Inner radius = 1 m

Iron sheet is 1 cm Thick

⇒ Solution :-

Let outer radius be R = Inner radius + thickness of iron sheet

= 101 cm

Inner radius be r = 1m = 100 cm

∴ Volume of the iron = (⅔)×(22/7)× (R^3-r^3)

(2/3)×(22/7)×(101^3-100^3)

44/21×30301 cm^3

63487.80952 cm^3

0.063487 cm^3