A hemispherical tank of radius 1 3/4 m. is full of water. A pipe connected to it empties it at the rate of 7 litres per second. How much time will it take to empty the tank?
Answers
Answered by
73
volume of hemispherical body=2/3 πr^3
=2/3 x 22/7 x (7/4)^3
=11.225 m^3
hence
volume of spherical body =11225 L
now,
time =volume/rate
=11225/7 =1603.58 sec
approximately time =1604 sec
=2/3 x 22/7 x (7/4)^3
=11.225 m^3
hence
volume of spherical body =11225 L
now,
time =volume/rate
=11225/7 =1603.58 sec
approximately time =1604 sec
Anonymous:
hey its is not a sphere its a hemisphere
hemisphere volume = 2 /3 pi r3
i think u reported so, i can't edit
as a brainly benefactor i have to ensure that correct answer is given to the user
its my duty to report wrong answer
okay no problem .
sorry for major mistake
hmm
Please edit your answer!
Answered by
66
Radius = 1 3/4 = 7 / 4 m
Volume = 2/3 πr³
= 2 / 3 × 22 / 7 × (7 / 4)³
= 2 / 3 × 22 / 7 × 343 / 64
= 11.2291667 m ³
= 11229.1667 litres
Water that falls in 1 sec = 7 Litres.
Time taken to empty the tank with 11229.1667 litres of water = 11229.1667 litres ÷ 7
= 1604.16667 sec
Volume = 2/3 πr³
= 2 / 3 × 22 / 7 × (7 / 4)³
= 2 / 3 × 22 / 7 × 343 / 64
= 11.2291667 m ³
= 11229.1667 litres
Water that falls in 1 sec = 7 Litres.
Time taken to empty the tank with 11229.1667 litres of water = 11229.1667 litres ÷ 7
= 1604.16667 sec
Ya, you are right.
Thank you!
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