a hemispherical vessel is made up of iron.if its outer diameter is 10cm and the thickness of the iron sheet used is 1cm then find the volume of iron required to make a vessel
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Considering the hemisphere is hollow.
outer diameter = 10 cm
outer radius = 5 cm
thickness = 1 cm
inner diameter = 10 -2 = 8 cm
inner radius = 4 cm
volume of the iron sheet required = (2/3)π[(5)³-(4)³] = 127.8 cm³
if we consider it closed then we have to take the base material also.
outer diameter = 10 cm
outer radius = 5 cm
thickness = 1 cm
inner diameter = 10 -2 = 8 cm
inner radius = 4 cm
volume of the iron sheet required = (2/3)π[(5)³-(4)³] = 127.8 cm³
if we consider it closed then we have to take the base material also.
sunny60:
but y u have taken 10-2
y not 10-1
reply fastttt
because diameter is a line segment which touches the both sides of a circumference
it touches both sides, so we have to subtract 2 from 10
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