Question

A heterozygous fair male had a conjugal interaction with a homozygous dark female. using an appropriate genetic diagram , explain the genotypic and the phenotypic appearance of the second felial generation of these parents. Note darkness is dominate over fairness.

Answer 1

Explanation:

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Answer 2

Answer:

Problem of inbreeding is one of the major problems of genetics. Since times of the human occurrence the population size was very small. People lived separate tribes. Therefore, consanguineous mating or inbreeding has been submitted enough. In process of the population size increase the intensity of such mating was reduced. But till now the consanguineous mating are present at small communities.

Inbreeding are widely submitted at animals. Very much frequently the man uses consanguineous mating of animals at artificial selection to receive useful properties of animals: speed of run, force, fleshiness, a plenty of milk, a wool, etc.

Let's consider principles of inbreeding in a family trees and a population.

Inbreeding in a Family Tree

There are family trees and populations where the principle panmictic mating is essentially broken. Usually it is geographically or socially relatively isolated small communities. In these communities the inbreeding i.e. consanguineous mating of various orders (a parent - a child, sibs, cousins, uncle - niece, etc.), can be wide-spread.

The problem of inbreeding influence on the population is the important problem of genetics 1. Now this problem yet has not received the final solution.

In most cases the inbreeding in a family tree take into account on three generations. It is the most distant relatives who are taken into account at consanguineous mating there is second cousins.

The inbreeding is taken into account with the help of inbreeding factor.

The inbreeding factor is the probability two alleles are identical by origin.

Let's consider the method of factor inbreeding factor calculation in a family tree offered by Wright 1, 2.

For the inbreeding factor finding it is necessary:

to find for the marrying descendants all ways in a family tree which through the common ancestor connect these descendants.

to count up number of steps (alternations of generations) on each way.

Then the inbreeding factor is equal:

……(1)

where r there is number of ways, m1, m2, ... mi- number of steps on each way.

Once again we shall note that the number of addends in the sum (1) is equal to number of ways which through the common ancestors connect marrying.