A hevy block of mass 25 kg. is to be dragged along horizantal surface with friction coeffecient 1/â3 then what is the minimum force required?
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Fmin =maximum frictional force acting on the block
Fmin =umg =1/3×25×10=250/3N =83.33N
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Fmin =umg =1/3×25×10=250/3N =83.33N
Hope it helps you
Please mark my answer as brainliest
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