A hexagonal lot with 4m,5m,6m,7m,8m and 2m dimensions of each side.
Please answer this with picture;(
Answers
Complete Question :- Learning Task 5 : Draw, label and find the perimeter of the following :-
1. A square with a side that measures 7 dm .
2. A rectangle with a length of 5cm and a width of 3cm .
3. A hexagonal lot with 4m, 5m,6m,7m,8m and 2m dimensions of each side .
4. A triangle with sides that measures 4cm, 5cm and 4cm .
Answer :-
In image rough diagram of all polygons is formed .
now,
→ Perimeter of square = 4 * side = 4 * 7dm = 28 dm .
→ Perimeter of rectangle = 2(Length + Breadth) = 2(5 + 3) = 16 cm .
→ Perimeter of irragular hexagon = sum of all sides = 4 + 5 + 5 + 7 + 8 + 2 = 31 m .
→ Perimeter of triangle = 4 + 5 + 4 = 13 cm .
Learn more :-
Construct a quadrilateral similar to a given quadrilateral with sides 4747 of the corresponding sides of ABCD
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