A highway is 14,500 km long. Peter starts from one end of the highway and covers a distance of 1,586 km on the first day, 2,200 km each day over the next four days and the remaining distance in another two days. Now, answer the following questions.
(a) How much distance did Peter cover over the last two days?
(b) How much distance did he cover in each of the last two days, assuming that he covered the same distance on both the days?
(c) What was the total distance covered by Peter in the first three days?
Answers
Step-by-step explanation:
(a) Peter covered a distance of 14,500 km - 1,586 km - 4 x 2,200 km = 4,114 km over the last two days.
(b) Let the distance covered by Peter on each of the last two days be x km. Since he covered the same distance on both days, the total distance covered over the last two days is 2x km. We know that he covered a total distance of 4,114 km over the last two days, so we can write:
2x km = 4,114 km
Solving for x, we get:
x = 4,114 km / 2 = 2,057 km
Therefore, Peter covered a distance of 2,057 km on each of the last two days.
(c) Peter covered a distance of 1,586 km on the first day and 2,200 km each day over the next three days. Therefore, the total distance covered by Peter in the first three days is:
Total distance = 1,586 km + 3 x 2,200 km = 8,386 km
Answer:
(a) the distance of the highway =1450km
then,
the covered the distance by Peter is 1st 5days =1587km+ 74 ×2200km
=1586+8800
=10386
so , he covered the distance in last two day =14500km-10386 =4114