Question

A hockey ball of mass 200 g travelling at 10 ms$^{-1}$ is truck by a hockey stick, so as to return it along its original path with a velocity of 5ms$^{-1}$ . Calculate the change in momentum that iccured in the motion of the ball, by the force applied by the hockey stick.​

Answer 1

Answer:

Mass of the hockey ball, m = 200 g = 0.2 kg

Hockey ball travels with velocity, v1 = 10 m/s

Initial momentum = mv1

Hockey ball travels in the opposite direction with velocity, v2 = −5 m/s

Final momentum = mv2

Change in momentum = mv1 − mv2 = 0.2 [10 − (−5)] = 0.2 (15) = 3 kg m s−1

Hence, the change in momentum of the hockey ball is 3 kg m s−1.

HOPE IT HELPS !!!!

Answer 2

Given:-

→Mass of the hockey ball(m) = 200g

→Initial velocity of (u) = 10m/s

→Final velocity of the ball(v) = 5m/s

To find:-

→Change in momentum occured in the motion of the hockey ball.

Solution:-

Firstly let's convert the mass of the ball from g to kg.

=> 1g = 0.001kg

=> 200g = 200×0.001

=> 0.2kg

•Final velocity of the ball will be -5m/s as the ball retraces it's path.

We know that Change in momentum (∆p) is :-

=> ∆p = Final momentum-Initial momentum

=> ∆p = mv-mu

=> ∆p = m(v-u)

=> ∆p = 0.2(-5-10)

=> ∆p = 0.2(-15)

=> ∆p = -3 kg m/s

[Negative sign represents that force is acting on the left direction]

Thus, the magnitude of Change in Momentum is 3 kg m/s.

Some Extra Information:-

•Momentum is defined as the quantity of motion contained in a body.

•Momentum is the product of mass and velocity of a body.

i.e. p = m×v

•Momentum has a sense of direction i.e. it is a vector quantity.