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A hole is drilled from the surface of earth to its centre. A particle is dropped from rest in the surface of earth in terms of its escape velocity on the surface of earth v_(e) is :

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Answered by mir77
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Answer:

A hole is drilled from the surface of earth to its center. A particle is dropped from rest at the surface of earth . The speed of the particle when it reaches the center of the earth in terms of escape velocity of the surface of earth $v_e$ is

\[(a)\;\frac{v_e}{2} \quad (b)\;v_e \quad (c)\; \sqrt 2 v_e \quad (d)\;\frac{v_e}{\sqrt 2}\]

Explanation:

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