Physics, asked by Rylias, 1 month ago

A hollow conducting sphere of radius 15 cm is charged such that the potential on its surface is 25 volts. The potential at a distance of 10 cm from the centre in volts is ___.

Answers

Answered by loverboy7284
2

Answer:

the full meaning of the full meaning of this message was automatically generated by the full meaning to see if you are u in snp cht in the place

Answered by HrishikeshSangha
0

The potential at distance 10 cm from the centre of the sphere is 25 volts.

Given,

Radius of the sphere=15 cm

Potential on the surface=25 volts.

To find,

the potential at a distance of 10 cm from the centre.

Solution:

Any charge given to a conductor resides on its outer surface.

Electric potential due to hollow conducting sphere having radius R:

(a)outside(r>R)

V=\frac{KQ}{r}

where,

V-electric potential

K=9X10^{9} \frac{Nm^{2} }{C^{2} }  (for air/vacuum)

Q-charge

r-distance from the centre.

(b)surface(r=R)

V=\frac{KQ}{R}

(c)inside(r<R)

V=\frac{KQ}{R}

The potential inside a spherical conductor(be it hollow or solid) is same everywhere.

So, potential due to the charge on the surface of the sphere is equal to potential due to the charge inside the sphere.

Thus, the potential at distance 10 cm from the centre of the sphere is 25 volts.

#SPJ2

Similar questions
Biology, 18 days ago