Question

if one of the zeroes of the polynomial 4x²-px +8 is 2 then the value of 2 is​

Answer 1

Answer:

substitute 2 in p(x)

p(x)= 4x²-px+8

p(2)= 4(2)²-p(2)+8

= 16-2p+8

= 24-2p

therefore 24-2p=0

-2p=-24

p=12