Question

A hollow cylinder of copper of length 25 cm and area of cross section 15 cm^2 , floats in water with 3/5 of its length inside water. Then

1)Apparent density of hollow copper cylinder is 0.6 g/cm^3
2) Weight of the cylinder is 225gf
3)Extra force required to completely submerged it in water is 150 gf
These are the answers please write the solutions​

Answer 1

Answer:

weight of cylinder will be 0.225 kg or 225 grams.

Explanation:

Length of the cylinder = 25 cm = 0.25 m

area of cross section = 15 cm² = 0.0015 m²

Hence volume of the cylinder = 0.25 x 0.0015 = 0.000375 m³

volume of the cylinder inside water = 3/5 x (0.000375) = 0.000225 m³

volume of water displaced = volume of cylinder inside water = 0.000225

=> weight of water displaced = density of water x volume of water

= 0.000225 x 1000

=0.225 kg

By the principle of flotation, the weight of the cylinder should be equal to the weight of the water displaced,

Hence weight of cylinder will be 0.225 kg or 225 grams.

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Explanation:

Answer 2

Answer:

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