Question

the digit in the tens place of a two digit number is three times that in the units place if the digits are reversed the new number will be 36 less than the original number find the original number check the solution ​

Answer 1

Answer:

62

Step-by-step explanation:

suppose digits are x & y where x is tens digit

then,

10x+y is the number

when digits are reverse the new number will be written as

10y+x

from the question,

(10x+y)-(10y+x)= 36

9x-9y = 36

9 (x-y)= 36

x-y=4 ............. .....................equation (1)

also,

in number tens digit is 3 time of unit placed digit

then,

x= 3y ............ ....................equation (2)

from equation 1 & 2,

3y-y = 4

2y = 4

y = 2

so from equation 2

x= 3y = 3×2 = 62

now the original number = 10x+y = 10×6+2 = 62