- A hollow cylindrical tube, open at both ends is made of 2 cm thick iron. If the external diameter is
50 cm and the length of the tube is 140 cm, find the volume of iron in it. Find the weight of the tube.
if 1 cm of metal weighs 8 g.
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Thickness =2cm
Ex.diameter=50cm
Therefore,Ex.radius=25cm
Now,In.radius=(25-2)cm
=23cm
Length=140cm
Therefore,Volume=
\pi ({ex.r}^{2} - {in.r}^{2} ) \times h
=22/7(625-529)×140
=22/7×96×140
=42240cu.cm
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