a hollow cylindrical tube open at both ends is made of iron 3 cm thick. if the external diameter be 56 cm n the length of the tube be 182 cm, find the number of cubic cm in it.
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Given : D =56 cm
d=56-3=53 cm
Height (h) =182 cm
Volume = (\pi x D^2 x h) /4 - (\pi x d^2 x h) /4
= 448040.32 - 401321. 83
=46718.49 cm^3
The number of cube will be 46718.
d=56-3=53 cm
Height (h) =182 cm
Volume = (\pi x D^2 x h) /4 - (\pi x d^2 x h) /4
= 448040.32 - 401321. 83
=46718.49 cm^3
The number of cube will be 46718.
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