a hollow iron pipe is 28 cm long and it's external diameter is 10 cm If the thickness of the pipe is 2 cm and iron weighs 8 g/cm3 then the weight of the pipe is
Answers
Answered by
2
Answer:
Correct option is
B
3.696kg
Volume of iron =π(R
2
−r
2
)×h
=π(4
2
−3
2
)×21
=
7
22
×(16−9)×21
=462cm
2
Weight =
1000
8×462
kg=3.696k
Answered by
2
The Weight of pipe is 11.264 kg.
A hollow iron pipe is 28 cm long and its external diameter is 10 cm If the thickness of the pipe is 2 cm and iron weighs 8 g/cm³.
We have to find the weight of the pipe.
First, we have to find the volume of iron pipe.
Volume of iron pipe = π(R² - r²)h
Here, outer radius , R = 10cm/2 = 5cm
inner radius, r = R - d = 5 cm - 2cm = 3 cm
[d is thickness of pipe ]
and h = 28 cm
∴ volume of pipe = 22/7 × (5² - 3²) × 28
= 88 × (25 - 9)
= 88 × 16
= 1408 cm³
Now the weight of pipe = volume of pipe × density of iron.
= 1408 cm³ × 8g/cm³
= 11264 g
= 11.264 kg
Therefore the Weight of pipe is 11.264 kg.
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