Math, asked by sanjana1809, 1 year ago

A hollow iron pipe, which is 14cm long and has its external diameter 10cm. If the thickness of the pipe is 2cm and iron weighs 10g/ cm³, find the weight of the pipe?

Answers

Answered by gautamisahoo

External radius(R)= 10-2= 5cm
Internal radius(r)= (5-2)= 3cm
l=14cm

Volume of the pipe= π(R²-r²)×l
   =π(25-9)×14
   = $\frac{22}{7}$ ×16×14
   =704cm³

Therefore weight of the pipe= volume×density
      =704cm³×10g/cm³
      =7040g
      =7.04kg

gautamisahoo: please mark as best

sanjana1809: Ok i will but how to mark best

Anonymous: There is a mistake.

gautamisahoo: there is an option

sanjana1809: Where is that option? It's not visible

gautamisahoo: its on top of my answer

sanjana1809: It's not there, tell me any anotherway

Anonymous: Hello there! There seems to be a mistake in your answer.

gautamisahoo: no thers not

sanjana1809: Ok tell me how to answer the questions posted here

Answered by Anonymous

R=5, r=3, l=14. Volume, V=Π(R²-r²)l=Π(16)(14)=Π(224)=22(32)=704. Mass, m=10(704)=7040gms. Mass of rod is 7.04 kgs

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