a hollow sphere of external and internal diameters 8cm and 4cm respectively is melted in to a cone of base diameter 8cm the height of cone (in cm) is
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First of all you allow this formula 1/4πrsquareh and then find the volume of cone and then subtract
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volume of sphere= volume of come
volume of external sphere-internal sphere =1/3pier2h
4/3pie(R3-r3)=1/3pie16h
4((4)3-(2)3)16h
4(64-8)=16h
4×56/16=h
h=14cm
volume of external sphere-internal sphere =1/3pier2h
4/3pie(R3-r3)=1/3pie16h
4((4)3-(2)3)16h
4(64-8)=16h
4×56/16=h
h=14cm
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