A hollow sphere of internal and external diameters 4 cm and 8cm respectively is melted to form a solid cylinder of base diameter 8 cm. the height of the cylinder is approximately:
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Sphere :
Inner diameter = 4cm
Inner radius = R₁ = 2 cm
Outer diameter = 8 cm
Outer radius = R₂ = 4 cm
ATQ,
Volume of sphere = volume of cylinder formed
(4/3)π(R₂³ - R₁³) = π r² h
4/3 (4³ - 2³) = 4² . h
4/3 (64 - 8) = 16 h
4/3 (56) = 16 h
(4/3). 56 /16 = h
14/3 = h
h = 4.67 cm
Inner diameter = 4cm
Inner radius = R₁ = 2 cm
Outer diameter = 8 cm
Outer radius = R₂ = 4 cm
ATQ,
Volume of sphere = volume of cylinder formed
(4/3)π(R₂³ - R₁³) = π r² h
4/3 (4³ - 2³) = 4² . h
4/3 (64 - 8) = 16 h
4/3 (56) = 16 h
(4/3). 56 /16 = h
14/3 = h
h = 4.67 cm
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